Hello.
I have to make an app that generated a random phone number.
XXX-XXX-XXXX
There can`t be any 8 or 9 digits in the first set.
There can`t be a number higher than 742 in the second. It says that it is possible to construct the number without determining each digit separately. I couldn`t figure out how to (if possible) define the first set without defining every dig separately, and wrote it this way:
Is there a way to do it they way the book asked? (without dig1, dig2, dig3)
(Classes introduced: String, Random, Math, NumberFormat, DecimalFormat, Wrapper, Enumerated Types, printf method).
I have to make an app that generated a random phone number.
XXX-XXX-XXXX
There can`t be any 8 or 9 digits in the first set.
There can`t be a number higher than 742 in the second. It says that it is possible to construct the number without determining each digit separately. I couldn`t figure out how to (if possible) define the first set without defining every dig separately, and wrote it this way:
Code:
import java.util.Random;
public class PhoneNumGen
{
public static void main (String[] args)
{
Random generator = new Random();
int dig1, dig2, dig3, digSet2, digSet3;
String phoneNumber;
dig1 = generator.nextInt(8);
dig2 = generator.nextInt(8);
dig3 = generator.nextInt(8);
digSet2 = generator.nextInt(743);
digSet3 = generator.nextInt (10000);
phoneNumber = (+dig1 +"" +dig2 +"" +dig3 +"-" + digSet2 +"-" + digSet3);
System.out.println ("Random phone number generated: " + phoneNumber);
}
}
Is there a way to do it they way the book asked? (without dig1, dig2, dig3)
(Classes introduced: String, Random, Math, NumberFormat, DecimalFormat, Wrapper, Enumerated Types, printf method).